Cs50 Tideman Solution Upd Review

return 0; } The implementation includes test cases to verify its correctness. For example, consider the following input:

int winner = check_for_winner(candidates_list, candidates); while (winner == -1) { // Eliminate candidate with fewest votes int eliminated = -1; int min_votes = voters + 1; for (int i = 0; i < candidates; i++) { if (candidates_list[i].votes < min_votes) { min_votes = candidates_list[i].votes; eliminated = candidates_list[i].id; } } Cs50 Tideman Solution

recount_votes(voters_prefs, voters, candidates_list, candidates); return 0; } The implementation includes test cases

eliminate_candidate(candidates_list, candidates, eliminated); int min_votes = voters + 1

3 3 1 2 3 1 3 2 2 1 3 This input represents an election with 3 voters and 3 candidates. The output of the program should be:

// Structure to represent a voter typedef struct voter { int *preferences; } voter_t;

count_first_place_votes(voters_prefs, voters, candidates_list, candidates);